Abattery and a resistor are wired into a circuit. the resistor dissipates 0.50 w. now two batteries, each identical to the original one, are connected in series with the resistor. part a what power does it dissipate?

The resistor dissipates 1 W when two identical batteries are connected in series.

Explanation:

Power dissipated is directly proportional to the Voltage and Current.

Connected in series, the total voltage of two batteries is equal to the sum of the voltage of each one.

If I double the applied voltage, the dissipated power will be double.

P = V*I

The losses that occurs inside any system, or the amount of deficiency that happens in any system's power and it is mainly due to the resistive elements in the circuit or system called as the power dissipation.

As, the Power can be calculated by analyzing the amount of Potential difference,V and the flow of current,I between any two points that are under-observation. While we can write it as,

P=V.I,

And the unit is, Watt,W.

While we are provided by the power dissipation value, that is about 0.50 W.

And the two batteries,V are connected in series with the resistors,R. And we have connection given to us in series. So, the current,I distribution will be same all across the circuit.

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.