Smoking tobacco is bad for your circulatory health. in an attempt to maintain the blood's capacity to deliver oxygen, the body increases its red blood cell production, and this increases the viscosity of the blood. in addition, nicotine from tobacco causes arteries to constrict. for a nonsmoker, with blood viscosity of 2.5×10−3pa⋅s, normal blood flow requires a pressure difference of 8.0 mm of hg between the two ends of an artery. if this person were to smoke regularly, his blood viscosity would increase to 2.7×10−3pa⋅s, and the arterial diameter would constrict to 90 % of its normal value.
what pressure difference would be needed to maintain the same blood flow in mm of hg?

It is d, all the other ones say incorrect answer .

No bc a lot of things r still theories n unproven

Scissors and a seesaw both cut things that’s the only comparison

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s