Two resistors, the first 12 ? and the second 6 2, are connected in parallel to a 48 v battery what is the power dissipated by each resistor? a) p1 144 w, p2-288 w b) p1-162 w, p2-324 w c) p1-180 w, p2-360 w d) p1-192 w, p2 384 w

P₁ = 192 W and P₂ = 384 W

Explanation:

It is given that,

Resistor 1,

Resistor 2,

Voltage, V = 48 V

Power dissipated by resistor 1 is given by :

P₁ = 192 watts

Power dissipated by resistor 2 is given by :

P₂ = 384 watts

So, the power dissipated by both the resistors is 192 watts and 384 watts respectively. Hence, this is the required solution.

im not to sure what it is

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explanation:

there is no change in the electric potential energy as it is in rest on both conditions.