The space shuttle rocket ship starts vertically upward from the launch pad acceleration of 6.5 m/sec^2. (a) find how much time it takes for the rocket ship to accelerate to 100 m/s. (b) at what height above the ground will the ship reach the velocity of 100 m/s?

(a) 15.4 second

(b) 769.23 m

Explanation:

u = 0, a = 6.5 m/s^2, v = 100 m/s

(a) Let t be the time taken

Use First equation of motion

v = u + a t

100 = 0 + 6.5 x t

t = 15.4 second

(b) Let height covered is h.

Use third equation of motion

v^2 = u^2 + 2 a h

100^2 = 0 + 2 x 6.5 x h

10000 = 13 x h

h = 769.23 m

divide the right side by the left side

0.024÷1.2=0.02 for example

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