In the derivation of the maximum likelihood estimate, probability distribution for a random vector y: we factorize the following conditional , y(m)|e(1) p(y((2) lz((m)(m) , x(m)) p(y x) p(y() m iip(y)) i=1 what assumptions justify this factorization? if we had not made any assumptions what would be a valid way to factorize the conditional distribution? 2. in the derivation of the maximum likelihood estimate, why is it okay to minimize the negative log likelihood instead of maximize the likelihood? 3. is mean squared error identical to the cost function derived by maximum likelihood? if there differences, are they important to the optimization problem? are 4. in the mean squared error, which of the depend on wj? m 2 (w0)-go) mse m 2=1 5. what is the partial derivative of mse with respect to συ'-1) 2 mse m i=1 ()fe 6. what is the partial derivative of with respect to w,? i) k 1 (e)e

wind moving at higher speeds will transfer more energy to the water, resulting in stronger waves.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr