An electromagnetic standing wave has a frequency of 120 mhz. (3396) problem 2: what is the distance (in m) between adjacent antinodes of this standing wave?

The distance between adjacent antinodes of the standing wave is 1.25 m.

Explanation:

Given that,

Frequency f= 120 MHz

We need to calculate the distance between adjacent antinodes of the standing wave

Using formula of distance

.....(I)

We know that,

Put the value of in to the equation (I)

Where, c = speed of light

f = frequency

Put the all value into the formula

Hence, The distance between adjacent antinodes of the standing wave is 1.25 m.

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

nah.   i'm just sleepy.