An automobile battery has an emf of 12.6 v and an internal resistance of 0.0600 ω. the headlights together present equivalent resistance 5.00 ω.(assumed constant) (a) what is the potential difference across the headlight bulbs when they are the only load on the battery? (b) what is the potential difference across the headlight bulbs when the starter motor is operated, taking an additional 35.0 a from the battery?

i dont know but

explanation:

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electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j