Aboy starts from point a and passes point c of a track abc shown in the figure. portion ab of length 1 is straight and portion bc is a semicircle of radius r (r< ). anywhere on the track, the modulus of the maximum acceleration of the hov is a find minimum transit time of the boy from a to c answer (-1) +2 2lr 2a

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5