An electron enters a magnetic field of 0.43 t with a velocity perpendicular to the direction of the field. at what frequency does the electron traverse a circular path? ( m el = 9.11 × 10-31 kg, e = 1.60 × 10-19 c)

Frequency,

Explanation:

It is given that,

Magnetic field, B = 0.43 T

We need to find the frequency the electron traverse a circular path. It is also known as cyclotron frequency. It is given by :

Hence, this is the required solution.

the answer is d. 4

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