Aparticle might be placed
1. inside a uniform spherical shell of mass m, but not at the center
2. inside a uniform spherical shell of mass m, at the center
3. outside a uniform spherical shell of mass m, a distance r from the center
4. outside a uniform solid sphere of mass m, a distance 2r from the center
rank these situations according to the magnitude of the gravitational force on the particle, least to greatest.
a) all tie
b) 1, 2, 3, 4
c) 1 and 2 tie, then 3 and 4 tie
d) 1 and 2 tie, then 3, then 4
e) 1 and 2 tie, then 4, then 3

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

not too sure thinking all accelerations are pointed down