An 8.0-ohm resistor and a 6.0-ohm resistor are connected in series with a battery. the potential difference across the 6.0-ohm resistor is measured as 12-v. (a) find the total resistance of the circuit. (b) find the current in the 6.0-ohm resistor. (c) find the potential difference across the battery.
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a) 14 Ω

b) 2.0 A

c) 28 V

Explanation:

a) The total resistance of resistors in series is the sum:

R = R₁ + R₂

R = 8.0 Ω + 6.0 Ω

R = 14 Ω

b) The current in the 6.0 Ω resistor can be found with Ohm's law:

V = IR

12 V = I (6.0 Ω)

I = 2.0 A

c) Since the resistors are in series, they have the same current.  So the total voltage is:

V = IR

V = (2.0 A) (14 Ω)

V = 28 V

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6 cos 34, 6 sin 34 trig