The drift speed in a copper wire is 4.08 × 10-5 m/s for a typical electron current. calculate the magnitude of the electric field inside the copper wire. the mobility of mobile electrons in copper is 4.5 × 10-3 (m/s)/(n/c). (note that though the electric field in the wire is very small, it is adequate to push a sizable electron current through the copper wire.)

9.07 x 10^-3 N/C

Explanation:

The mobility of electrons is defined as the ratio of drift velocity to the applied electric field.

Vd = 4.08 x 10^-5 m/s

Mobility = 4.5 x 10^-3 m/s

Let the electric field is E.

Mobility = Vd / E

E = Vd / mobility

E = 4.08 x 10^-5 / (4.5 x 10^-3)

E = 9.07 x 10^-3 N/C

the area between the graph and the t axis

yo yo yo its papaguy in the house lol

okay, ima .

um it shows links to uh so kinda microsoft website is that were ima go or no? ?