You are exploring a newly discovered planet. the radius of the planet is 7.20 × 107 m. you suspend a lead weight from the lower end of a light string that is 4.00 m long and has mass 0.0280 kg. you measure that it takes 0.0685 s for a transverse pulse to travel from the lower end to the upper end of the string. on earth, for the same string and lead weight, it takes 0.0370 s for a transverse pulse to travel the length of the string. the weight of the string is small enough that its effect on the tension in the string can be neglected. assuming that the mass of the planet is distributed with spherical symmetry, what is its mass? express your answer with the appropriate units. m=

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

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explanation:

connect the batteries in series and hope