A) why is the following inverse b decay forbidden for a free proton? p net+v b) why is the same reaction sometimes possible if the proton is bound in a nucleus? for example, the following reaction occurs: 13 c) how much energy is released in the reaction in given in b)? take the atomic masses to be m18c) 0.000549 u 13.003355 u and m( 15n) 13.005739 u, and the electron mass to be m(e+)

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

+15-35=-20

going in opposite directions

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m