In a certain cyclotron a proton moves in a circle of radius 0.740 m. the magnitude of the magnetic field is 0.960 t. (a) what is the oscillator frequency? (b) what is the kinetic energy of the proton?

Part a)

Part b)

Explanation:

Part a)

As we know that radius of circular path of a charge moving in constant magnetic field is given as

now we have

now the frequency of oscillator is given as

PART b)

now for kinetic energy of proton we will have

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.