Compute the diameter of a square link subjected to a compres- sive load of 27,000 lbs. modulus of elasticity 30 x 106 psi. proportionality limit 38,000 psi, working stress - 7000 psi, length of the link 55 in.

The diameter of a square link is 0.0233 inch.

Explanation:

Given that,

Load = 27000 lbs

Modulus of elasticity

Working stress

length l = 55 in

We need to calculate the diameter of a square link

Using formula of stress

Put the value into the formula

Hence, The diameter of a square link is 0.0233 inch.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.