Focal lengths in the fourth lab (the one with the lenses), you graphed the inverse of the image distance (1/d,) against the inverse of the object distance (1/do). how did you find the focal length of your lens from this graph? the thin lens equation

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

its a circle not a square that's simple silly.

explanation:

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