friction 1. i am hauling 230㎏ of firewood on a sled, puig with 710n of force on a rope over my shoulder at a 72 degree angle from the sled. the sled starts to accelerate at 0.12mis. what is the coefficient of friction between the ground and the sled? 2. there is a 4kg book sitting on a table. igive the book a push·ltstarts off sling at 25msec then slides to a stop in 1.7m. what is the coefficient of friction between the book and the table? 3. the 1992 1500kg mazda rx-7 could go from 60mph-0 in 119ft. what is the coefficient of friction between the tires and the tarmac? 4. i am walking down a 20 degree slope and i step on a banana peel with a kinetic coefficient of friction of 0.013. assuming i have a mass of 120kg, how fast do i start sliding down that hil?

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

i think the answer is a, hope this is right, that would be my best guess.

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015