The distance between two successive minima of a transverse wave is 3.10 m. five crests of the wave pass a given point along the direction of travel every 14.7 s. (a) find the frequency of the wave. hz (b) find the wave speed. m/s

The frequency is 0.34 Hz and the wave speed is 1.05 m/s.

Explanation:

Given that,

The distance between two successive minima of a transverse wave is wavelength.

Wavelength = 3.10 m

Time = 14.7 s

(I). We need to calculate the frequency

(II). We need to calculate the wave speed

Formula of wave speed

Where,

Put the value into the formula

Hence, The frequency is 0.34 Hz and the wave speed is 1.05 m/s.

d) physical means can be used to separate the components of air.

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.