A60.0-kg crate rests on a level floor at a shipping dock. the coefficients of static and kinetic friction are 0.760 and 0.410, respectively. what horizontal pushing force is required to (a) just start the crate moving and (b) slide the crate across the dock at constant speed? important: assume that the pushing force is to the right

(a) 446.88 N

(b) 241.08 N

Explanation:

m = 60 kg, μs = 0.760, μk = 0.410

(a) To just start the crate moving: the coefficient of friction is static.

F = μs m g

F = 0.760 x 60 x 9.8

F = 446.88 N

(b) To slide the crate with constant speed: the coefficient of friction is kinetic.

F = μk m g

F = 0.410 x 60 x 9.8

F = 241.08 N

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.