How far from a converging lens with a focal length of 16 cm should an object be placed to produce a real image which is the same size as the object? express your answer using two significant figures.

32 cm

Explanation:

f = focal length of the converging lens = 16 cm

Since the lens produce the image with same size as object, magnification is given as

m = magnification = - 1

p = distance of the object from the lens

q = distance of the image from the lens

magnification is given as

m = - q/p

- 1 = - q/p

q = p                                    eq-1

Using the lens equation, we get

1/p + 1/q = 1/f

using eq-1

1/p + 1/p = 1/16

p = 32 cm

a=d/t

a="triangle"v/t

explanation:

a = acceleration

option number c is the right answer.