Aparticle with a charge of -2.7 ? c and a mass of 3.8 x 10-6 kg is released from rest at point a and accelerates toward point b, arriving there with a speed of 36 m/s. the only force acting on the particle is the electric force. what is the potential difference vb - va between a and b? if vb is greater than va, then give the answer as a positive number. if vb is less than va, then give the answer as a negative number.

0.0018 V

Explanation:

According to the law of conservation of energy, the kinetic energy gained by the particle is equal to the electric potential energy lost:

where

is the mass of the particle

is the final speed of the particle

q = -2.7 C is the charge

is the potential difference between the two points

Solving for , we find

The particle has been accelerated by this potential difference: since it is a negative charge, it means that the particle has moved from a point at lower potential towards a point of higher potential.

So, since the initial point is A and the final point is B, the result is

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