How much heat is needed to raise the temperature of 8grams of water by 19°c

635.36J

Explanation:

The formulae to apply in this question is;

q=m*c*ΔФ  where q is the heat needed, m is mass,c is specific heat capacity and ΔФ is change in temperatures

Given that;

m=8 g

ΔФ= 19°C - 0°C= 19°C

c=4.18J/g.°C

Substitute values

q= 8×4.18×19 = 635.36J

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explanation: