At the instant shown during deceleration, the velocity of an automobile is 40 ft/s to the right. knowing that the velocity of the contact point a of the wheel with the ground is 5 ft/s to the right, determine (a) the instantaneous center of rotation of the wheel, (b) the velocity of point b, (c) the velocity of point d.

spare some change and give it to the poor

explanation:

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energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j