Why do noble gases not form compounds readily?

Noble gases have what is known as a stable octet of electrons - the completeness of this outer shell of electrons legislates the reactivity of the compound. For example, Sodium, in its elemental form, has only one electron in the outermost shell - this makes it extremely reactive with other elements. As you move to the right of the periodic table, the shell begins to fill and the relative reactivity decreases. Once the shell is full, the need to react no longer exists. Forming any bonds would actually result in an unfavorable coupling, so naturally occurring compounds are practically nonexistent.

Hope this helps!

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.