Particle a of charge 3.06 10-4 c is at the origin, particle b of charge -5.58 10-4 c is at (4.00 m, 0), and particle c of charge 1.07 10-4 c is at (0, 3.00 m). we wish to find the net electric force on c.

Indoraptor for sure

You need to be more specific.  i really don't know what a "motion map" is.you can draw a graph of an object's position, distance, displacement, speed,velocity, or acceleration versus time, or you can draw a graph of the object's x-position versus its y-position and not give any information about time at all.if the graph presents position or displacement against time,  then constant velocity is a straight line . . i.e. a line that has  constant slope.if the graph shows speed against time, then constant velocityis a horizontal piece of line.if the graph shows acceleration against time, then constant  velocity is a piece of line that lies on the x-axis . . it's value is zero. 

20hope i helep

En espanol amigo por favor