Photoelectrons with a maximum speed of 7.0 x 10^5 m/s are ejected from a surface in the presence of light with a frequency of 8.00 x 10^14 hz. calculate the energy required to eject photoelectrons from the surface

The energy required to eject photoelectrons from the surface is

Explanation:

Given:

Speed of the photo electron=

Frequency of the photoelectron=

To Find:

The energy required to eject photoelectrons from the surface.

Solution:

Energy of the photon is given by

E = hf

Where,

E = energy of the photons

h = Planck’s constant and its value is

Substituting the values in the formula we get ,

E = hf

Result:

Thus a energy of is required to eject thephotoelectrons from the surface

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