When a fixed amount of ideal gas goes through an isobaric expansion a) its internal (thermal) energy does not change. b) the gas does no work. c) no heat enters or leaves the gas. d) its temperature must increase. e) its pressure must increase.

Explanation:

In an isobaric process the pressure remains constant, which means the initial pressure and the final pressure will be the same.

In addition, during this thermodynamic process, the volume of the ideal gas expands or contracts in such a way that the variation of pressure is neutralized.

Now, according to the First law of Thermodynamics that establishes the conservation of energy:

  (1)

Where:

is the internal energy

is the heat transferred

is the work

Now, for an isobaric process:

   (2)

Where:

is the pressure (always positive)

is the volume variation of the gas

Here we have two possible results:

-If the gas expands (positive ), the work is positive.

-If the gas compresses (negative ), the work is negative.

In this case we are talking about the first result (work is positive).

Then, according to the above, equation (1) can be written as follows:

  (3)

Clearing :

   (4)

Then, for an ideal gas in an isobaric process, part of the heat () added to the system will be used to do work (positive in this case) and the other part will increase the internal energy, hence the temperature will increase as well.

i would think form in reponse to tensional forces

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards