Ahelicopter is 8.50 m above the ground and climbing at 2.5 m/s. it drops a package from rest (relative to the helicopter). at the moment that the package is released, what is its velocity relative to the ground?

2.5 m/s

Explanation:

The velocity of the package relative to the ground = the velocity of the package relative to the helicopter + the velocity of the helicopter relative to the ground

v = 0 m/s + 2.5 m/s

v = 2.5 m/s

At the moment it is released, the package is rising at 2.5 m/s.