Calculate the current through r2.

calculate the current through r1.

calculate the potential drop across r2.

calculate the total power developed in the circuit.

calculate the total resistance.

calculate the potential drop across r1.

Explanation:

I posted the exact question and this is what someone sent me if u understand it let me know cuz i dont

The total resistance is 15 Ω, the total current is 1A, The potential drop in R1 and R2 are 10V and 5V respectively and the total power develped is 15 W.

Explanation:

First it is necessary to simplify the circuit. We can do this by calculating the total or equivalent resistance Re. For series resistance arrangement, Re is computed as:

RT = R1 + R2 = 5 Ω + 10 Ω = 15 Ω

According to Ohm’s law the total current can be calculated dividing the total voltage V by Re:

I = V/Re = 15V/15Ω = 1A  

This current will be the same current through R1 and R2. Then we can compute the potential drop across R2 multiplying the current across R1 by the resistance:

VR1 = I*R2 = 1 A * 10 Ω = 10 V  

The potential drop across R2 is obtained in the same way as R1, considering R2 resistance:

VR2 = I*R1 = 1 A * 5Ω = 5 V

The total power could be calculated multiplying the total current I by the total voltage:

P = I*V = 1 A * 15 V = 15 W

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.