Tyhe mass of an object is 117 g adding 1200j of heat will raise the temperture of the object by 12 celsius what is the specifc heat of the object a 0.35 j/g *k b 6.8 j/g *k c 0.85 j/g*k d 42 j/g*k

C 0.85 j/g*k

Explanation:

The specific heat capacity of a material is given by:

where

Q is the amount of heat supplied to the object

m is the mass of the object

is the increase in temperature of the object

For the object in this problem, we have

m = 117 g is the mass

Q = 1200 J is the heat supplied

is the increase in temperature

Substituting into the formula, we find the specific heat:

this means that the temperature of both substances will be equal

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.