Aspring required a force of 5.0 n to compress it 0.1 m. how much work is required to stretch the spring 0.4 m

20N

Explanation:

The force (Hooke's Law) is proportional to the deformation. To extend the spring 4 times longer, you will need 4 times the force. In total, 20 N

4Joules

F=-kx

E=1/2kx^2

5N=-k(.01m)

k=50N/m

E=1/2kx^2

E=1/2(50N/m)(0.4m)^2

E=4Joules

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.