Atrain is moving at a constant speed on a surface and inclined at 10 degrees with the horizontal travels a distance of 400 m in 5 seconds. calculate the vertical velocity component of the train during the time period.

13.9 m/s

Explanation:

The velocity of the train along the inclined surface is given by the ratio between the distance travelled, d, and the time taken, t:

where we have

d = 400 m

t = 5 s

Substituting,

This is the velocity of the train along the inclined plane. Now we can find the vertical component of the velocity by using the formula:

where is the angle of the slope. Substituting, we find