Aproton accelerates from rest in a uniform electric field of 635 n/c. at some time later, its speed is 1.30 × 106 m/s. what is the magnitude of its acceleration? the mass of a proton is 1.6726 × 10−27 kg and the fundamental charge is 1.602 × 10−19 c . answer in units of m/s 2 . 031 (part 2 of 4) 10.0 points how long does it take the proton to reach this speed? answer in units of s. 032 (part 3 of 4) 10.0 points how far has it moved in this time interval? answer in units of m. 033 (part 4 of 4) 10.0 points what is its kinetic energy

1)

The force experienced by the proton is

where

is the proton charge

is the strength of the electric field

Substituting into the equation,

The acceleration of the proton is given by Newton's second law:

where

is the force exerted on the proton

is the proton's mass

Substituting,

2)  

We can use the following equation:

where

is the acceleration of the proton

is the final velocity

u = 0 is the initial velocity

t is the time

Solving the equation for t, we find

3) 13.86 m

The distance travelled by the proton is given by the equation

where

u = 0 is the initial velocity

s the time

is the acceleration of the proton

Substituting,

4)

The final kinetic energy of the proton is given by

where we have

is the proton's mass

is the final velocity

Substituting into the formula,

the answer is a. hope this .

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