Asample of gas has a volume of 25l at a pressure of 200 kpa and a temperature of 25°c. what would be the volume if the pressure were increased to 250 kpa and the temperature were decreased to 0°c?

18 L

Explanation:

Use ideal gas law:

PV = nRT

Find initial number of moles, but first convert to units that match the gas constant units.

(200,000 Pa) (0.025 m³) = n (8.314 Pa m³ / mol / K) (25 + 273.15 K)

n = 2.017 mol

At the new pressure and temperature:

(250,000 Pa) V = (2.017 mol) (8.314 Pa m³ / mol / K) (0 + 273.15 K)

V = 0.018 m³

V = 18 L

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft