Planet z-34 has a mass equal to 1/3 that of earth, a radius equal to 1/3 that of earth, and an axial spin rate 1/2 that of earth. with representing, as usual, the acceleration due to gravity on the surface of earth, the acceleration due to gravity on the surface of z-34 is g/9. 9g. g/3. 3g. 6g.

3g

Explanation:

The acceleration of gravity on the surface of a planet is given by

where

G is the gravitational constant

M is the mass of the planet

R is the radius of the planet

Calling M the mass of the Earth, R its radius, and g its acceleration due to gravity, we have

is the mass of planet Z-34

is the radius of Z-34

We can ignore the different spin rate since the gravitational acceleration does not depend on that

So, the value of g on planet Z-34 will be

so, the correct answer is 3g

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