Abike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4m .determine the acceleration of the bike.

Explanation:

Let acceleration of the bike is a m/sec^2 bike started from rest so its initial speed will zero i.e.u=0

It reaches at a speed of 7.10 m/s i.e final

speed v= 7.10 m/s

In reaching speed 7.10 m/s ,it covered distance 35.4 m. Apply equation of motion which relates

u ,v,a and s

V^2=u^2+2 as

So acceleration of the bike which started from rest, reaches at speed of 7.10 m/s by travelling distance 35.4 m will be 0.712 m/ sec^2.