An object is placed a distance of twice the focal length away from a diverging lens. what is the magnification of the image?

-1/3
+1/3
-2/3
-3/2
+2/3
+3/2

+1/3

Explanation:

The lens equation states that:

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

For a diverging lens, the focal length is negative:

and we also know that the object is placed a distance of twice the focal length, so

So we can find q from the equation above

And the magnification of the image is given by

answer would be d.) i hope this

explanation:

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explanation:

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