How much work is done using a 500 w microwave for 5 minutes

Explanation:

The power used by an object is defined as:

where

W is the amount of work done by the object

t is the time taken

In this problem, we have:

P = 500 W is the power of the microwave

is the time taken

So we can solve the formula for W, the work done by the microwave:

electrical power

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s