A10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. the magnitude of the block's momentum is

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

b. lifting dumbbell weight at 20-degree angle from the body after a 45-degree angle

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.