Aguitar string with a linear density of 2.0 g/m is stretched between supports that are 60cm apart. the string is observed to form a standing wave with three antinodes when driven at a frequency of 420 hz. what are (a) the frequency of the fifth harmonic of this string and (b) the tension in the string?

(a) 700 Hz

For standing waves on a string, the number of antinodes (n) corresponds to the order of the harmonic. So, three antinodes corresponds to the third harmonic. Also, the frequency of the nth-harmonic is the nth-integer multiple of the fundamental frequency, so we have:

where is the fundamental frequency. Solving for f1, we find

And so now we can find the frequency of the 5th-harmonic:

(b) 56.4 N

The fundamental frequency of a string is given by:

where we have:

L = 60 cm = 0.60 m is the length of the string

is the linear density

T = ? is the tension in the string

Solving the formula for T and using the fundamental frequency, f1=140 Hz, we find

gans

explanation:

vestigial organs (like your appendix) are organs that no longer serve a purpose.

answer: strength i guess

explanation: