The force needed to lift an object is equal in size to the gravitational force on the object. how much work is done in lifting an object that has a mass of 5 kg a vertical distance of 2 m?

! i offer many points for an

Work done in lifting the object = 98 J

Explanation:

Work: Work can be defined as the product of force and distance.

The S.I unit of work is Joules (J).

Mathematically it can be expressed as

W = F × d Equation 1

Where W = work done, F = force needed to lift the object, d = distance

The gravitational force on the object = Weight of the object

Weight of the object = mg Equation 2

Where m = mass of the object, g = acceleration due to gravity

Given: m = 5 kg,

Constant: g = 9.8 m/s²

Substituting these values into equation 2

Weight of the object = 5 × 9.8

Weight of the object = 49 N

Since weight of the object = force needed to lift the object,

F = 49 N

Also Given: d = 2 m

Substituting these values into equation 1

W = 49 × 2

W = 98 J

Work done in lifting the object = 98 J

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

f=ma newton

f=100x2.5=250n