An object with a mass of 500 kg is dropped from a tall crane. after having fallen 70 % of the total distance to the ground, the object has a potential energy of 44100 joules. what is its kinetic energy at this time?

102900 Joules

Explanation:

Assuming the kinetic energy was zero at the moment of release, you can make the following argument to solve the problem:

The potential energy at full height was mgh. We are told that after 70% of the distance, i.e., mg(0.3h) = 44.1kJ. Since potential energy is linear in altitude h, we get get the full potential energy to be 44.1kJ/0.3. The difference between full potential energy and the one after 70% of the way must equal the gained kinetic energy (neglecting stuff like heat due to friction). So,

44.1kJ/0.3 - 44.1kJ = 0.7*44.1kJ/0.3 = 102.9kJ = Ekinetic

The kinetic energy after 70% of the falling distance was 102.9 kJ.

so easy. just google the electromagnetic waves and it’ll pop up.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force