The aorta in an average adult has a cross-sectional area of 2.0 cm^2. calculate the flow rate of blood of 1.0 g/cm^3 in the aorta if the flow speed is 43 cm/s. answer in units of g/s. (i did this part and the correct answer is 86) assume that the aorta branches to form a large number of capillaries with a combined cross-sectional area of 2.9 × 10^3 cm^2. what is the flow speed in the capillaries? answer in units of cm/s.

As we know that flow rate will always remains the same

so here the flow rate from aorta = flow rate through large capillaries

so here we will have

flow rate through Aorta =

now we can also say that flow rate through capillaries is given by

as we know that

now from above formula

so the speed will be 0.0296 cm/s through capillaries

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).