Calculate the magnitude of the force between two 3.60 mc point challenges 9.3 cm apart

Q = magnitude of charge on each of the two point charge = 3.60 mC = 3.60 x 10⁻³ C

r = distance between the two point charges = 9.3 cm = 0.093 m

k = constant = 9 x 10⁹ Nm²/C²

F = magnitude of the force between the two point charges = ?

according to coulomb's law , force between two charges is given as

F = k Q²/r²

inserting the values

F = (9 x 10⁹) (3.60 x 10⁻³)²/(0.093)²

F = 1.35 x 10⁷ N

the body's situation won't change the forces are equal opposit and on the same body