Astone is dropped from a tower 100 meters above the ground. the stone falls past ground level and into a well. it hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. calculate the depth of the well. given: g = -9.81 meters/second2. a. 22.5 meters b. 50.7 meters c. 100 meters d. 110 meters e. 152.45 meters

Option A: 22.5 m

Explanation:

A stone is dropped from a tower. The initial velocity of the stone, u = 0.

Height of the tower, y = 100 m

Let the depth of the well be d.

Time taken of the drop of the stone, t = 5 s

The stone falls under acceleration due to gravity g = 9.81 m/s²

We will use second equation of motion:

s = u t + 0.5 g t²

⇒100 m + d = 0 + 0.5 × 9.81 m/s²× (5.00 s)²

⇒d = (122.6 - 100) m = 22.6 m ≅ 22.5 m

Thus, the correct option is A. The depth of the well is 22.5 m.

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