Jenna lifts a 5 kg mass through a displacement of 2 m in 3 s. how much time does kendra need to lift a 10 kg mass through a distance of 1m in order to have the same power output.

Power = (work done) / (time to do the work)

Work done = (force) / (distance moved in the direction of the force)

The work for the first mass is (5 kg) x (g) x (2 m) = 10g Joules.

The work for the 2nd mass is (10 kg) x (g) x (1 m) = 10g Joules.

as long as Jenna lifts both masses on the same planet, the amount of work is going to be the same in both cases.  So in order to have the same power output, she would have to do both jobs in the same amount of time.  If she did the first one in 3 seconds, then the second one also requires 3 seconds.

the components of a vector are the parts of the vectors that are to each other.

b perpendicular

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y