What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 288 k? use the equation: 1/2 mv^2 = 3/2 nrt for m, use 0.01000 kg. remember that r = 8.31 j/(mol x k)

The average velocity of the atoms 847.33 m/s.

Explanation:

Moles of the neon = 1.00

Temperature of the gas : 288 K

Mass of the gas = 0.01000

R = 8.31 J/mol K

The average velocity of the atoms 847.33 m/s.

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

amplitude

hope this