Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball traveling at 10 m/s. a 50 kg ball traveling at 20 m/s would have kinetic energy. a 50 kg ball traveling at 5 m/s would have kinetic energy. a 50 kg person falling at 10 m/s would have kinetic energy.

The formula for kinetic energy is  KE = (1/2) (mass) (speed²)

== The 50 kg ball traveling at 10 m/s has some kinetic energy.  

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = 4 times as much kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.

== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.

The kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.

Given data:

The mass of ball is, m = 50 kg.

The speed of ball is, v = 10 m/s.

The another value of speed is, v' = 20 m/s.

The third value of speed is, u = 5 m/s.

The fourth value of speed is, u' = 10 m/s.

The standard expression for kinetic energy is given as,

KE = (1/2)mv²

here,

m is the mass and v is the speed of the object.

For 50 kg ball traveling at 10 m/s, the kinetic energy is,

KE = (1/2)(50)(10)²

KE = 2500 J

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = 4 times as much kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.

== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.

Thus, we can conclude that the kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.

Learn more about the kinetic energy here:

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