In a cricket match, the 0.16kg ball is bowled with a straight arm. during one particular delivery, the ball leaves the bowler's hand horizontally, with a speed relative to the ground of 80.8 mph. the bowler's arm is 0.64 m long and the bowler is running at 10.0 mph when the ball is released. calculate the centripetal force exerted on the ball in the bowler's hand, in n. note: 1 mph = 0.447 ms^-1.

412.1 N

Explanation:

First of all let's calculate the total speed of the ball as it is released, which is equal to the speed of the ball + the speed of the bowler:

Now let's convert it into m/s. We know that

So

And now we can calculate the centripetal force, which is given by:

where

m = 0.16 kg is the mass of the ball

v = 40.6 m/s is the speed of the ball

r = 0.64 m is the radius of the circular path (equal to the length of the bowler's arm)

Substituting:

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.